1892 United States House of Representatives elections
Charles Frederick Crisp Democratic Charles Frederick Crisp Democratic The 1892 United States House of Representatives elections were held for the most part on November 8, 1892, with Oregon, Maine, and Vermont holding theirs early in either June or September.
They coincided with the election of Grover Cleveland as president for the second, noncontinuous, time, defeating incumbent Benjamin Harrison.
They were the first elections after reapportionment following the 1890 United States census, increasing the size of the House.
The Republican pickups were a result of a number of Republican-friendly Northern districts reverting to form after voting Democratic in the previous election cycle.
The third party Populists, who had high support among farmers and laborers in the Southern United States and the Western United States, also gained three seats.
| House seats by party holding plurality in state | ||
|---|---|---|
|
80+% Democratic
|
80+% Populist
|
80+% Republican
|
|
60+% to 80% Democratic
|
60+% to 80% Populist
|
60+% to 80% Republican
|
|
Up to 60% Democratic
|
Up to 60% Republican
|
|
| Net gain in party representation | ||
|---|---|---|
|
6+ Democratic gain
|
6+ Republican gain
|
|
|
3-5 Democratic gain
|
3-5 Republican gain
|
|
|
1-2 Democratic gain
|
1-2 Populist gain
|
1-2 Republican gain
|
|
no net change
|
||