Third-seeded Margaret Osborne duPont defeated Louise Brough 4–6, 6–4, 15–13 in the final to win the women's singles tennis title at the 1948 U.S. National Championships.

[1][2] The seven seeded U.S. players are listed below.

Margaret Osborne duPont is the champion; others show in brackets the round in which they were eliminated.

[3]