1948 United States presidential election in Missouri

Harry S. Truman Democratic Harry S. Truman Democratic The 1948 United States presidential election in Missouri took place on November 2, 1948, as part of the 1948 United States presidential election.

Voters chose 15[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Incumbent President Harry S. Truman won his home state of Missouri with 58.11% of the popular vote against Republican Governor of New York Thomas E. Dewey, who gained 41.49% of the popular vote.

[3][4] As of the 2020 presidential election[update], this is the last election in which Moniteau County and Cole County voted for a Democratic presidential candidate.

[5][6] Truman dramatically improved upon Franklin D. Roosevelt's performance in the state four years prior, winning the state by more than 16 percentage points, compared to Roosevelt's 3 percentage points.