1988 United States presidential election in Wyoming

Wyoming was won by incumbent United States Vice President George H. W. Bush of Texas, who was running against Massachusetts Governor Michael Dukakis.

Wyoming weighed in for this election as 14.3 percentage points more Republican than the national average.

[1] Bush won the election in Wyoming with a solid 22-point landslide, sweeping all 23 of the state's counties.

Bush's vote share of 60.53% made Wyoming his third-best state in the region (after Utah and Idaho), and his sixth-best overall (after Utah, New Hampshire, Idaho, South Carolina, and Florida).

Along with New Hampshire, Nevada, Delaware, and Maine, it was also one of five states where every county voted for Bush.