2018 WPA World Nine-ball Championship

[3] The reigning champion was Filipino Carlo Biado, who defeated his compatriot Roland Garcia 13–5 in the 2017 final.

[4][5] Biado would reach the final of the event, defeating Shane Van Boening in the semi-final.

Germany's Joshua Filler won the event, defeating Biado in the final 13–10.

[6] The event was entered by 128 participants who were initially divided into 16 groups of 8 players, in which they competed against each other from December 14 to 16 in a double elimination tournament.

[9] Later in the event, 9-ball world number one Klenti Kaci was defeated in the round of 32 – 10–11 to 17 year old Robbie Capito.