The event's final was contested by Scots Stephen Maguire and John Higgins who had won the 2019 World Cup doubles competition as a pair earlier in the season.

Kyren Wilson won the previous year's event, but lost in the first knockout round to David Gilbert 4–6.

[1] The 2019 Six-red World Championship was a professional invitational snooker event held between 2 and 7 September 2019.

[4][5] Defending champion Kyren Wilson progressed alongside Thailand's amateur player Passakorn Suwannawat in group A.

The group also contained one of the tournament's two female players in Reanne Evans, plus Noppon Saengkham.

[4] Gary Wilson defeated three-time world champion Mark Selby 5–4 in the second round of matches to progress.

[4] David Gilbert won group F ahead of 2019 World Seniors Championship winner Jimmy White in second.

Dott joined Williams in the knockout round after a defeat of Thailand's Thepchaiya Un-Nooh.

The 2014 winner Stephen Maguire defeated Jimmy White 6–5 despite being behind at 3–5, and won the match on the final black ball.

[9] The sole remaining Thai player Passakorn Suwannawat lost in the last 16 to Ali Carter 5–6.

[11] In a rematch of the 2019 World Snooker Championship semi-final, Dave Gilbert played John Higgins in the quarter-final.

[12] After taking all of the first four frames, Mark Williams defeated Stuart Bingham 6–3 to set up a rematch of the 2018 World Snooker Championship final against Higgins.

The match was contested between two players who had formed the winning Scotland pair at the 2019 World Cup, Maguire and Higgins.

Positions within the group were decided by the number of matches won and then, in the event of a tie, by frame difference.