Albany is a town in Delaware and Randolph counties in the U.S. state of Indiana, along the Mississinewa River.

[8] As of the census[1] of 2020, there were 2,295 people, 946 households, and 528 families living in the town.

There were 1,057 housing units at an average density of 542.1 per square mile (209.3/km2).

46.2% of Albany residents were employed, working a mean of 40.8 hours per week.

The median gross rent in Albany was $576 and the homeownership rate was 76.7%.

111 housing units were vacant at a density of 56.9 per square mile (22.0/km2).

As of the 2010 Census,[10] there were 2,165 people, 924 households, and 602 families living in the town.

There were 1,060 housing units at an average density of 605.7 per square mile (233.9/km2).

30.7% of all households were made up of individuals, and 12.9% had someone living alone who was 65 years of age or older.

As of the 2000 Census,[11] there were 2,368 people, 958 households, and 646 families living in the town.

28.8% of all households were made up of individuals, and 13.7% had someone living alone who was 65 years of age or older.