Floris is a city in Davis County, Iowa, United States.

[4] Floris is located on the south margin of the Soap Creek floodplain.

[5] According to the United States Census Bureau, the city has a total area of 0.48 square miles (1.24 km2), all land.

There were 58 housing units at an average density of 99.0 per square mile (38.2/km2).

There were 62 housing units at an average density of 129.2 per square mile (49.9/km2).

24.1% of all households were made up of individuals, and 20.6% had someone living alone who was 65 years of age or older.

There were 68 housing units at an average density of 140.6 per square mile (54.3/km2).

26.2% of all households were made up of individuals, and 16.4% had someone living alone who was 65 years of age or older.

About 21.4% of families and 22.4% of the population were below the poverty line, including 31.7% of those under the age of eighteen and none of those 65 or over.