Geneva is a city in Franklin County, Iowa, United States.

[4] According to the United States Census Bureau, the city has a total area of 0.42 square miles (1.09 km2), all land.

There were 73 housing units at an average density of 178.6 per square mile (69.0/km2).

Hispanic or Latino persons of any race comprised 1.5% of the population.

There were 74 housing units at an average density of 176.2 per square mile (68.0/km2).

32.4% of all households were made up of individuals, and 16.1% had someone living alone who was 65 years of age or older.

There were 77 housing units at an average density of 180.3 per square mile (69.6/km2).

34.8% of all households were made up of individuals, and 23.2% had someone living alone who was 65 years of age or older.

None of the families and 5.9% of the population were living below the poverty line, including no under eighteens and 8.5% of those over 64.