Humboldt is a town in Brown County in the U.S. state of Wisconsin.

According to the United States Census Bureau, the town has a total area of 24.0 square miles (62.2 km2), all of it land.

[3] As of the census[2] of 2000, there were 1,338 people, 453 households, and 370 families residing in the town.

There were 460 housing units at an average density of 19.2 per square mile (7.4/km2).

15.7% of all households were made up of individuals, and 6.6% had someone living alone who was 65 years of age or older.