In mathematics, a linearised polynomial (or q-polynomial) is a polynomial for which the exponents of all the constituent monomials are powers of q and the coefficients come from some extension field of the finite field of order q.
We write a typical example as
for some fixed positive integer
This special class of polynomials is important from both a theoretical and an applications viewpoint.
[1] The highly structured nature of their roots makes these roots easy to determine.
In general, the product of two linearised polynomials will not be a linearized polynomial, but since the composition of two linearised polynomials results in a linearised polynomial, composition may be used as a replacement for multiplication and, for this reason, composition is often called symbolic multiplication in this setting.
Notationally, if L1(x) and L2(x) are linearised polynomials we define
when this point of view is being taken.
are q-associates (note: the exponents "qi" of L(x) have been replaced by "i" in l(x)).
More specifically, l(x) is called the conventional q-associate of L(x), and L(x) is the linearised q-associate of l(x).
Linearised polynomials with coefficients in Fq have additional properties which make it possible to define symbolic division, symbolic reducibility and symbolic factorization.
Two important examples of this type of linearised polynomial are the Frobenius automorphism
and the trace function
In this special case it can be shown that, as an operation, symbolic multiplication is commutative, associative and distributes over ordinary addition.
[3] Also, in this special case, we can define the operation of symbolic division.
If L(x) and L1(x) are linearised polynomials over Fq, we say that L1(x) symbolically divides L(x) if there exists a linearised polynomial L2(x) over Fq for which:
If L1(x) and L2(x) are linearised polynomials over Fq with conventional q-associates l1(x) and l2(x) respectively, then L1(x) symbolically divides L2(x) if and only if l1(x) divides l2(x).
[4] Furthermore, L1(x) divides L2(x) in the ordinary sense in this case.
[5] A linearised polynomial L(x) over Fq of degree > 1 is symbolically irreducible over Fq if the only symbolic decompositions
with Li over Fq are those for which one of the factors has degree 1.
Note that a symbolically irreducible polynomial is always reducible in the ordinary sense since any linearised polynomial of degree > 1 has the nontrivial factor x.
A linearised polynomial L(x) over Fq is symbolically irreducible if and only if its conventional q-associate l(x) is irreducible over Fq.
Every q-polynomial L(x) over Fq of degree > 1 has a symbolic factorization into symbolically irreducible polynomials over Fq and this factorization is essentially unique (up to rearranging factors and multiplying by nonzero elements of Fq.)
For example,[6] consider the 2-polynomial L(x) = x16 + x8 + x2 + x over F2 and its conventional 2-associate l(x) = x4 + x3 + x + 1.
Theorem: If A is a nonzero affine polynomial over
with all of its roots lying in the field
an extension field of
, then each root of A has the same multiplicity, which is either 1, or a positive power of q.