Milford is a town in Decatur County, Indiana, United States.

[5] According to the United States Census Bureau, the town has a total area of 0.1 square mile (0.2 km2), all land.

There were 54 housing units at an average density of 602.1 per square mile (232.5/km2).

Of the 48 households 29.2% had children under the age of 18 living with them, 60.4% were married couples living together, 8.3% had a female householder with no husband present, and 22.9% were non-families.

There were 12.2% of families and 15.9% of the population living below the poverty line, including 3.4% of under eighteens and 11.5% of those over 64.