Nevada (/nɪˈveɪdə/ niv-AY-də) is a village in Wyandot County, Ohio, United States.

[5] According to the United States Census Bureau, the village has a total area of 1.03 square miles (2.67 km2), all land.

There were 334 housing units at an average density of 324.3 per square mile (125.2/km2).

26.4% of all households were made up of individuals, and 10.2% had someone living alone who was 65 years of age or older.

There were 328 housing units at an average density of 317.8 per square mile (122.7/km2).

24.9% of all households were made up of individuals, and 13.1% had someone living alone who was 65 years of age or older.