Pembroke Park is a town in Broward County, Florida, United States.

[10] On its north: On its northeast: On its northwest: On its south: On its southeast: On its southwest: On its east: On its west: As of the 2020 United States census, there were 6,260 people, 2,428 households, and 1,489 families residing in the town.

[13] As of the 2010 United States census, there were 6,102 people, 2,323 households, and 1,429 families residing in the town.

33.7% of all households were made up of individuals, and 15.1% had someone living alone who was 65 years of age or older.

[16] It was also the fifth most British West Indian populace, at 1.1% (tied with Gordon Heights, New York,)[17] the twelfth highest percentage of Jamaican residents in the US, at 8% of the city's population,[18] and the 137th highest percentage of Cuban residents in the US, at 1.52% of the city's population (tied with Goldenrod, Florida.