In mathematics, the Pettis integral or Gelfand–Pettis integral, named after Israel M. Gelfand and Billy James Pettis, extends the definition of the Lebesgue integral to vector-valued functions on a measure space, by exploiting duality.
The integral was introduced by Gelfand for the case when the measure space is an interval with Lebesgue measure.
is a normed space or (more generally) is a Hausdorff locally convex TVS.
Evaluation of a functional may be written as a duality pairing:
is called weakly measurable if for all
A weakly measurable map
Common notations for the Pettis integral
To understand the motivation behind the definition of "weakly integrable", consider the special case where
is the underlying scalar field; that is, where
is just scalar multiplication by a constant), the condition
with the map scalar-valued functional on
is identified as a vector subspace of the double dual
is a semi-reflexive space if and only if this map is surjective.
An immediate consequence of the definition is that Pettis integrals are compatible with continuous linear operators: If
for real- and complex-valued functions generalises to Pettis integrals in the following sense: For all continuous seminorms
The right-hand side is the lower Lebesgue integral of a
Taking a lower Lebesgue integral is necessary because the integrand
This follows from the Hahn-Banach theorem because for every vector
An important property is that the Pettis integral with respect to a finite measure is contained in the closure of the convex hull of the values scaled by the measure of the integration domain:
This is a consequence of the Hahn-Banach theorem and generalizes the mean value theorem for integrals of real-valued functions: If
, then closed convex sets are simply intervals and for
a Borel measure that assigns finite values to compact subsets,
is quasi-complete (that is, every bounded Cauchy net converges) and if
is weakly measurable and there exists a compact, convex
be a sequence of Pettis-integrable random variables, and write
denote the sample average.
Suppose that the partial sums
in the sense that all rearrangements of the sum converge to a single vector
The weak law of large numbers implies that
[citation needed] To get strong convergence, more assumptions are necessary.