Rose Hill is a city in Mahaska County, Iowa, United States.

[3] According to the United States Census Bureau, the city has a total area of 0.14 square miles (0.36 km2), all of it land.

There were 72 housing units at an average density of 506.4 per square mile (195.5/km2).

There were 85 housing units at an average density of 607.1 per square mile (234.4/km2).

23.6% of all households were made up of individuals, and 1.4% had someone living alone who was 65 years of age or older.

There were 91 housing units at an average density of 666.7 per square mile (257.4/km2).

25.6% of all households were made up of individuals, and 3.7% had someone living alone who was 65 years of age or older.

About 16.0% of families and 14.0% of the population were below the poverty line, including 6.5% of those under the age of eighteen and 17.2% of those 65 or over.