Saxeville is a town in Waushara County, Wisconsin, United States.

As of the census[2] of 2000, there were 974 people, 393 households, and 312 families residing in the town.

There were 610 housing units at an average density of 16.9 per square mile (6.5/km2).

There were 393 households, out of which 28.5% had children under the age of 18 living with them, 70.7% were married couples living together, 5.1% had a female householder with no husband present, and 20.6% were non-families.

18.1% of all households were made up of individuals, and 6.9% had someone living alone who was 65 years of age or older.