Seymour is a town in Eau Claire County, Wisconsin, United States.

The unincorporated community of Seymour is located in the southwestern portion of the town.

As of the census[2] of 2000, there were 2,978 people, 1,108 households, and 863 families residing in the town.

There were 1,151 housing units at an average density of 36.9 per square mile (14.3/km2).

16.1% of all households were made up of individuals, and 5.7% had someone living alone who was 65 years of age or older.