Buck Grove is a city in Crawford County, Iowa, United States.

[4] According to the United States Census Bureau, the city has a total area of 0.36 square miles (0.93 km2), all land.

There were 17 housing units at an average density of 46.1 per square mile (17.8/km2).

There were 19 housing units at an average density of 52.8 per square mile (20.4/km2).

27.8% of all households were made up of individuals, and 5.6% had someone living alone who was 65 years of age or older.

There were 21 housing units at an average density of 57.3 per square mile (22.1/km2).

30.0% of all households were made up of individuals, and 15.0% had someone living alone who was 65 years of age or older.

There were no families and 10.0% of the population living below the poverty line, including no under eighteens and none of those over 64.