The Calabi triangle is a special triangle found by Eugenio Calabi and defined by its property of having three different placements for the largest square that it contains.
[1] It is an isosceles triangle which is obtuse with an irrational but algebraic ratio between the lengths of its sides and its base.
[2] Consider the largest square that can be placed in an arbitrary triangle.
It may be that such a square could be positioned in the triangle in more than one way.
The triangle △ABC is isosceles which has the same length of sides as AB = AC.
If the ratio of the base to either leg is x, we can set that AB = AC = 1, BC = x.
Let H be the foot of the perpendicular drawn from the apex A to the base.
Let □IJKA be a square on base AC with its side length as b.
, we can get the following equation: If x is the largest positive root of Calabi's equation: we can calculate the value of x by following methods.
and Then f is monotonically increasing function and by Intermediate value theorem, the Calabi's equation f(x) = 0 has unique solution in open interval
The value of x is calculated by Newton's method as follows: The value of x can expressed with complex numbers by using Cardano's method: The value of x can also be expressed without complex numbers by using Viète's method: The value of x has continued fraction representation by Lagrange's method as follows:[1, 1, 1, 4, 2, 1, 2, 1, 5, 2, 1, 3, 1, 1, 390, ...] = The Calabi triangle is obtuse with base angle θ and apex angle ψ as follows: The rational approxmation of x is h95/k95 and an error bounds ε is as follows: