Cauchy formula for repeated integration

The Cauchy formula for repeated integration, named after Augustin-Louis Cauchy, allows one to compress n antiderivatives of a function into a single integral (cf.

Cauchy's formula).

For non-integer n it yields the definition of fractional integrals and (with n < 0) fractional derivatives.

Let f be a continuous function on the real line.

Then the nth repeated integral of f with base-point a,

is given by single integration

A proof is given by induction.

The base case with n = 1 is trivial, since it is equivalent to

}}\int _{a}^{x}{(x-t)^{0}}f(t)\,\mathrm {d} t=\int _{a}^{x}f(t)\,\mathrm {d} t.}

Now, suppose this is true for n, and let us prove it for n + 1.

Firstly, using the Leibniz integral rule, note that

}}\int _{a}^{x}(x-t)^{n}f(t)\,\mathrm {d} t\right]={\frac {1}{(n-1)!

}}\int _{a}^{x}(x-t)^{n-1}f(t)\,\mathrm {d} t.}

Then, applying the induction hypothesis,

{\displaystyle {\begin{aligned}f^{-(n+1)}(x)&=\int _{a}^{x}\int _{a}^{\sigma _{1}}\cdots \int _{a}^{\sigma _{n}}f(\sigma _{n+1})\,\mathrm {d} \sigma _{n+1}\cdots \,\mathrm {d} \sigma _{2}\,\mathrm {d} \sigma _{1}\\&=\int _{a}^{x}\left[\int _{a}^{\sigma _{1}}\cdots \int _{a}^{\sigma _{n}}f(\sigma _{n+1})\,\mathrm {d} \sigma _{n+1}\cdots \,\mathrm {d} \sigma _{2}\right]\,\mathrm {d} \sigma _{1}.\end{aligned}}}

Note that the term within square bracket has n-times successive integration, and upper limit of outermost integral inside the square bracket is

Thus, comparing with the case for n = n and replacing

of the formula at induction step n = n with

Putting this expression inside the square bracket results in

}}\int _{a}^{x}(x-t)^{n}f(t)\,\mathrm {d} t.\end{aligned}}}

This completes the proof.

The Cauchy formula is generalized to non-integer parameters by the Riemann–Liouville integral, where

α ∈

( α ) > 0

, and the factorial is replaced by the gamma function.

The two formulas agree when

α ∈

Both the Cauchy formula and the Riemann–Liouville integral are generalized to arbitrary dimensions by the Riesz potential.

In fractional calculus, these formulae can be used to construct a differintegral, allowing one to differentiate or integrate a fractional number of times.

Differentiating a fractional number of times can be accomplished by fractional integration, then differentiating the result.