Daniel is a town in Wasatch County, Utah, United States.

The population was 938 at the 2010 census, at which time it was a township and census-designated place (CDP).

[5] According to the United States Census Bureau, the CDP had a total area of 3.8 square miles (9.8 km2), all land.

There were 259 housing units at an average density of 69.1 per square mile (26.7/km2).

9.2% of all households were made up of individuals, and 2.9% had someone living alone who was 65 years of age or older.