Franklin is a town in Kewaunee County, Wisconsin, United States.

[3] As of the census[2] of 2000, there were 997 people, 338 households, and 270 families residing in the town.

There were 359 housing units at an average density of 10.1 per square mile (3.9/km2).

There were 338 households, out of which 38.5% had children under the age of 18 living with them, 67.8% were married couples living together, 6.5% had a female householder with no husband present, and 20.1% were non-families.

14.8% of all households were made up of individuals, and 6.5% had someone living alone who was 65 years of age or older.