Mazeppa (Russian: Мазепа) is a 1909 Russian drama film directed by Vasili Goncharov.
[1][2][3][4] The film tells about the Hetman named Mazepa, who is in love with Kochubey's daughter, Maria, and asks her father for consent to marry her, but his father refuses him.
This does not stop them and they run away...[5] This article related to a Russian film of the 1900s is a stub.
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