Sageville is a city in Dubuque County, Iowa, United States.

[3] According to the United States Census Bureau, the city has a total area of 0.69 square miles (1.79 km2), all land.

There were 44 housing units at an average density of 52.6 per square mile (20.3/km2).

There were 57 housing units at an average density of 82.6 per square mile (31.9/km2).

27.3% of all households were made up of individuals, and 14.5% had someone living alone who was 65 years of age or older.

There were 95 housing units at an average density of 151.8 per square mile (58.6/km2).

29.4% of all households were made up of individuals, and 9.4% had someone living alone who was 65 years of age or older.

About 8.6% of families and 14.8% of the population were below the poverty line, including 26.3% of those under the age of eighteen and 18.2% of those 65 or over.