Sheffield Lake is a city in Lorain County, Ohio, United States.

[5] According to the United States Census Bureau, the city has a total area of 2.48 square miles (6.42 km2), all land.

[6] As of the census[11] of 2010, there were 9,137 people, 3,721 households, and 2,481 families living in the city.

There were 4,093 housing units at an average density of 1,650.4 per square mile (637.2/km2).

27.0% of all households were made up of individuals, and 7.6% had someone living alone who was 65 years of age or older.

There were 3,776 housing units at an average density of 1,497.1 per square mile (578.0/km2).

21.7% of all households were made up of individuals, and 7.0% had someone living alone who was 65 years of age or older.