Alexandrovsk-Sakhalinsky District (Russian: Алекса́ндровск-Сахали́нский райо́н) is an administrative district (raion) of Sakhalin Oblast, Russia, one of the seventeen in the oblast.

[1] As a municipal division, it is incorporated as Alexandrovsk-Sakhalinsky Urban Okrug.

[3] It is located in the west of the oblast.

The area of the district is 4,777.4 square kilometers (1,844.6 sq mi).

[citation needed] Its administrative center is the town of Alexandrovsk-Sakhalinsky.