In geometry, Archimedes' quadruplets are four congruent circles associated with an arbelos.
[1][2][3] An arbelos is formed from three collinear points A, B, and C, by the three semicircles with diameters AB, AC, and BC.
The other two quadruplet circles are formed in a symmetric way from the semicircle with radius r2.
According to Proposition 5 of Archimedes' Book of Lemmas, the common radius of Archimedes' twin circles is: By the Pythagorean theorem: Then, create two circles with centers Ji perpendicular to HE, tangent to the large semicircle at point Li, tangent to point E, and with equal radii x.
Using the Pythagorean theorem: Also: Combining these gives: Expanding, collecting to one side, and factoring: Solving for x: Proving that each of the Archimedes' quadruplets' areas is equal to each of Archimedes' twin circles' areas.