Liberty, Outagamie County, Wisconsin

As of the census[2] of 2000, there were 834 people, 267 households, and 230 families residing in the town.

There were 283 housing units at an average density of 9.2 per square mile (3.6/km2).

There were 267 households, out of which 44.2% had children under the age of 18 living with them, 80.5% were married couples living together, 3.0% had a female householder with no husband present, and 13.5% were non-families.

10.9% of all households were made up of individuals, and 3.0% had someone living alone who was 65 years of age or older.

About 0.9% of families and 0.8% of the population were below the poverty line, including none of those under the age of eighteen or sixty-five or over.