In the International System of Units, the position of the moving object is measured in meters relative to the origin, while the time is measured in seconds.
Placing position on the y-axis and time on the x-axis, the slope of the curve is given by: Here
Therefore, the slope of the curve gives the change in position divided by the change in time, which is the definition of the average velocity for that interval of time on the graph.
, or the derivative of the position with respect to time.
A similar fact also holds true for the velocity vs. time graph.
, or the derivative of the velocity with respect to time (or the second derivative of the position with respect to time).
Since the velocity of the object is the derivative of the position graph, the area under the line in the velocity vs. time graph is the displacement of the object.
The same multiplication rule holds true for acceleration vs. time graphs.
When acceleration is multiplied The expressions given above apply only when the rate of change is constant or when only the average (mean) rate of change is required.
If the velocity or positions change non-linearly over time, such as in the example shown in the figure, then differentiation provides the correct solution.
Differentiation reduces the time-spans used above to be extremely small (infinitesimal) and gives a velocity or acceleration at each point on the graph rather than between a start and end point.
The derivative forms of the above equations are Since acceleration differentiates the expression involving position, it can be rewritten as a second derivative with respect to time: Since, for the purposes of mechanics such as this, integration is the opposite of differentiation, it is also possible to express position as a function of velocity and velocity as a function of acceleration.
The process of determining the area under the curve, as described above, can give the displacement and change in velocity over particular time intervals by using definite integrals: