Oakley is a census-designated place (CDP) in Lincoln County, Wyoming, United States.

[3] According to the United States Census Bureau, the CDP has a total area of 0.18 square mile (0.47 km2), all land.

[4] As of the census[2] of 2000, there were 18 people, 9 households, and 5 families residing in the CDP.

44.4% of all households were made up of individuals, and 22.2% had someone living alone who was 65 years of age or older.

There were no families and 10.5% of the population living below the poverty line, including no under eighteens and 40.0% of those over 64.