Iridium(IV) iodide is a binary chemical compound of iridium and iodide with the chemical formula IrI4.

[1][2][3] Iridium(IV) iodide can be obtained by reacting dipotassium hexachloroiridate or hexachloroiridic acid with an aqueous solution of potassium iodide.

[4][5] Iridium tetraiodide forms black crystals, does not dissolve in water and alcohol.

[6][7][8] In alkali metal iodide solutions, the compound dissolves easily to give a ruby red solution, forming complex salts.

[5] The compound decomposes when heated:[citation needed] Iridium(IV) iodide can be used as a catalyst in organic chemistry.